Fractions
 4/7 of a pole is in the mud. When 1/3 of it is pulled out, 250 cm of the pole is still in the mud. Find the full length of the pole .

 1000
 1100
 950
 1050
 None of the above

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Let us assume length of pole is L.
Length of the pole in Mud is = L x 4/7 = 4L/7
Length of the Pole which is pulled out = L x 1/3 = L/3
Length of the pole is still in mud = Length of the pole in Mud  Length of the Pole which is pulled out
Length of the pole is still in mud = 4L/7  L/3
According to question,
Length of the pole is still in mud = 250
4L/7  L/3 = 250
Solve the equation and find the answer.Correct Option: D
Let us assume length of pole is L.
Length of the pole in Mud is = L x 4/7 = 4L/7
Length of the Pole which is pulled out = L x 1/3 = L/3
Length of the pole is still in mud = Length of the pole in Mud  Length of the Pole which is pulled out
Length of the pole is still in mud = 4L/7  L/3
According to question,
Length of the pole is still in mud = 250
4L/7  L/3 = 250
(4L x 3  L x 7)/7 x 3 = 250
12L  7L = 250 x 21
5L = 250 x 21
L = 250 x 21/5
L = 50 x 21
L = 1050